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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
; \, T0 d' M5 \" _. q7 p4 ]6 _. p, Q$ m& i+ g% j. ]
假设大路开这样的路:4 v# `/ q2 x# p- ^- Y4 } k
* a m4 {. j4 e( A$ L6 j' q* x$ U7 H9 m8 ~
12121212121212121212121212121212。& E, L M5 T- N) V
& j# K9 P8 e) ^. m4 b- s
按2珠路,就是BPBPBPBPBP。+ f* A& D/ z5 w- R& p) _
1 R* \2 R* ^9 M K* h 如果我们去掉第一口,就会出现完全相反的结果:
8 j7 k% X) O; c {: W* }
' W( ~3 i' b2 P% C; l$ E 21212121212121212121212121212121。
% c" U9 K& s6 T1 x" `& c9 L: E. K" P! y8 z$ |
变成了PBPBPBPBPB。2 X+ R1 z, q0 U V) S6 k# {. ^* `
( E$ Q1 @" B% d* w8 D7 s
如果我们再去掉一口,又返回第一种情况了。) u/ D- h4 @4 `8 U x' ]# {: V6 z+ q
3 U/ Y$ b( j# P' a2 ?* K" T4 c: k x
所以每一条大路,按2珠路排列,有2种不同的路数。
e0 `* `9 N H, s! r T a8 z
1 W6 ^5 f9 E7 g; Z$ h: t, ] 再举一个列子:
( [5 r0 ^* o8 Q& v; Z) b5 D+ {
+ s0 Z1 x$ z! H$ q* a, Q6 \ r 大路:122122122122122122。
8 y2 {, u/ V, |% o, ^! J+ L- s/ L
$ ~6 T% D( |( L+ o. e: l* F 按三珠路排列:
2 m7 ^% Q1 v1 g# z" K) h2 G6 N% T$ t. E" H( `" z* I; ~4 Y5 i. o3 [
122,122,122,122,122,122。0 a4 s- t3 |0 N. T5 P7 ^
% |8 |8 ]' O: M: m, F9 X& i5 j& ^
去掉第一口,变成:
& F6 R7 k# W7 A1 Z# z; L& S9 b! t! C. X- Q3 i
221,221,221,221,221,去掉前2口,变成:
8 G; _4 I$ n8 p; \" s
3 {4 B( S& I6 N 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。$ e6 y0 W: K9 a9 M* A8 W/ s
) s+ D. r: p/ U; E, k: t 同理:按N珠路排列,有N种不同的路数。
* Y; m6 D; z0 a
. A3 o3 ?4 m% L4 e1 V 我提出这个的意义在于:& N l% C4 C0 ~$ n, l0 x: A! a
. X$ a3 z. A i+ T/ {" V 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
! ~# I X/ `$ U9 y/ b$ ^$ l1 v, O* G4 G+ Q3 U
2、为三多理论提供了下注的多面性奠定基础。. W. c% `: @' \& l$ |
; S3 [7 G x5 x7 k6 E( F" I 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
) q+ }3 _; E4 T4 |! ?/ m" ^" f' }. P C$ M B- p
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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