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[lastpost] => 2796704 【星宝】1月13日投注流水30000元 1768440545 舞出精彩
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。# i! r8 u9 p# B
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一般来说,. c) e7 F$ U' D* l
6 m( X; ]3 s# U. g6 E: X3 c二连赢的概率是25%9 v3 Y, k& b) C) M2 i; Y: o
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三连赢的概率是12.5%9 c! H; J& \/ C" m
) e7 |$ c' Q4 T+ q3 U( b8 Q' u四连赢的概率是6.25%
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) l( @( a3 a" N `……
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十连赢的概率是0.09765625%! ^( O7 ?& L, @: S8 M, k
4 c+ ~, h. i& b, _5 n& z/ R这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。$ R6 |3 }' _. l9 ~+ g7 s
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百家乐的真实概率含义是:# d6 x }7 v: T; v2 P# D
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假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球8 t6 e' h6 i: g% N( W5 \ ^1 ?
$ p3 }& M+ f/ }5 H% p# F0 U/ Z1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。
4 E/ a& }% K, q7 e9 I, ]% E6 G# X8 U$ K+ s. e# x1 U( [
你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。 C& @4 ^( V2 u7 N b: R4 C& ^& w) [
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。" e c6 D; q- H
$ n7 c# z7 w. [- ^7 `1 ~另外一个说法是,
3 H: `" |! @, y5 R h" }2 h8 j3 s1 t( N0 m0 p3 S+ m8 X
1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。0 k6 `, b! S$ ]# ]& X4 }. |
+ U# L' {( O) F3 @8 v2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
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再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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+ C, ?5 ]( S/ |/ s& T平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。3 ]* `7 _" H0 `$ E
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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3 P; I! V. s6 i: }4 j3 Z4 v举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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第三,凯利公式的问题在于:形而上学。8 ]. J. b9 l& `: d
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。/ @0 g* o( B3 a4 E# n
0 E' N/ j; ]) m" d# @& x事实上,你玩的时候,基本上每次都能打到。! p, j6 F9 m3 f' t% \( G; @
" T' J( c, O2 K# U/ [' q因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。% E, w% z5 E, y, d% n
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