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[lastpost] => 2651265 【E世博】5月20日投注流水64267元(单日流水) 1716303371 如梦的生活
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以下是输给那破游戏不甘心后的乱想..如有错误请提出或无视.. 首先是豹子问题, |* O5 K8 s- t' I9 S- a
# ]: g8 [7 I% @- [
因为太郁闷..所以从排列组合开始..( K) b% t; O/ o' d0 m. \; R3 m
5 p; T( J7 P* d3 S7 y假设直线A上有N个点,取任意点都有相同程度的概率.那么有2个取点者同时随即取点E,2者同时取得点E的概率是E/N*N( o8 w8 r( T+ E: s) g
# l+ F" r' T" n% s- i! a6 ]那么豹子的出现概率是2/216=0.00926=0.926%
) l5 W! C5 V5 @5 `( c) e: j; E, w3 c5 C! h A$ _" n" J1 q
豹子的赔率是30那么收益期望为0.2778风险为99.074%$ f4 a" ~6 j1 j
, U) x& f) Y6 e) ^* F6 [
连续2次出现率为42.67%的负4次方(大概是大型超市抽奖活动的特等奖的概率..有信心的可以玩下)
2 ?7 w" H5 t0 L8 y# H" J* W: y' _
4 V% O5 [: i3 p; N @在是压大小问题.3 S+ C3 d: f+ ~. k; N! S* C; J2 o
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根据以上得出每组大小的概率是49%..
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由此可见..压大小就总合来说是必败的0 X: P0 u/ y9 G6 J: G! E
9 Q' a, t" }7 d" ~: H1 m8 m) i
心理学中有个叫赌徒效应还是啥啥的..是说随即序列发生一个事件的概率与之前发生的事件无关。即发生的概率并没有因先前发生的事件而增加。) M( _* q2 N! A6 ]
; f( `( a. P$ I j3 P+ Y1 l' ]也就是说,压大小实际上永远就是49%概率压对。
" F6 _; e4 Y4 W$ R0 g1 I1 y
' [ y" O/ ^- S& f, W% T8 E并非这次压错了.下次就是50%了
. v' J. r! q( f. d. n8 {
' N0 e& \5 c) u& r/ |由此可见压大小以综合来说必输.压豹子其收益价与风险值不成比列。- N& b* @$ B5 O* g, N3 B' \
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根据以上分析.还是奉劝大家!远离DB! [6 P+ v" i0 c9 M4 A/ g2 W
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还有..以上是有实际验证的~昨天赌了上百回资金流动大概有成千上万..损失了进两百$ O0 P/ w7 V8 o- O" K' N
: i5 ?+ s7 P- P. h/ i, d9 }今天中午又赌了N次..资金流动上千..损失了30左右..均与以上概率成比例~ 嘛- -偶赌的还算比较厉害了..输的惨就不去说了~~那位上千的全没了# d, [6 F7 o: [# V/ G# `
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偶决定在也不赌了~真的...
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必输的东西也是要来旁观了啊,这么的东西还是值得学学的 |
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