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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
1 y8 J& l* }) X G+ Q
, z7 X0 T1 Q; d/ y' ^ S 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)
( W, U! ?$ o2 e2 t% F" n# s5 s, |% w4 R
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)
, {( [8 O) I" c5 s: R/ M$ m" e
5 L3 f6 F( Y7 V 第二行:O X X O O OX O X (第二行开始出现洞); n: @1 u$ K/ k. k4 p9 x# {; \
# U; i/ c. {) O) _4 b5 ]9 I 第三行:O X O X X
* ^& W9 x. }' l3 c1 R
! W1 y2 t' \0 e. X6 a7 F 第四行:O X X# f2 s) h5 v% E" }
4 f* l5 l, G, s1 y6 k+ ?- u5 ^
第五行: X& m. M( t7 U2 {/ \2 F2 e; j O0 a
( O9 R/ D4 w# U+ F1 e5 K 那么新写出来的大路是怎么样的呢?* } ~* e" L Q& c0 |0 q$ ~7 a% j
) M. o; }: {; W7 K" |6 g% R 记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。
8 g7 \" ]& @$ u& p- a' f1 ]2 y6 h' }$ G/ ]
如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)
1 e2 o* m8 z6 s$ i: N
/ c' c. T2 A3 w# e' y* [: M 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)( m5 t% t; B5 N: k+ j& |4 l4 h* i
1 A& D" Q3 O0 f4 k* I- R 第二行:OOXXXOOX XXXXX (第二行也是全满的)
r" W) w, E/ j' P3 w G0 y) S. G0 E3 P6 b" f% P" e# \9 G
第三行:OX OX XO XOOX (第三行才出现洞)4 \1 r' }4 x9 R" B' h
5 W9 a. A+ k d7 @ 第四行:O XO O XXX 3 M0 o3 J5 f/ n/ z2 V& I
; V- N& V% F! p. Q* h
第五行: O. d+ q m$ O1 B
0 i$ I- C# E; q: E/ t 通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。
, o& a: c: A A) d+ a- \0 S$ A
) j8 ^+ o: X) Q& V0 ~( W 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。8 N: M- M5 ~! v8 O
4 c7 ? b: n. M0 d
通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。- u3 c! k9 Y# k4 n0 F
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