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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O+ t0 P$ w4 P5 s
4 S' _$ M; D& x8 P发现了一个有趣的现象，
+ ?' @" y) y& R% X每一条大路，( L& G3 F- }" Z
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
* s4 a/ A5 I( l3 d$ f0 L按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
% r' m' G1 a% E$ k按4珠路排列，有4种不同的路数
1 z* t6 r* P$ R7 b! b7 F按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C; k* O: u' h4 n) Y5 ~" s* k' i" G
什么意思呢，可能大家一时不清楚，: L- O9 m- a& L/ N% t
我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
5 W7 v t# k0 w假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u% W! t/ A' K% m. l3 J6 A5 i8 M
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
. a; @1 q L$ C8 l8 O& ]( [够极端了吧. l: ~/ J7 j! Z' i I* `: u
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
& D+ u! L" c# I如果我们去掉第一口，就会出现完全相反的结果：6 p% s! x; W; u1 n L0 ~
212121212121212121212121212121216 t3 q2 p3 s8 ?- T" `8 r* y
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C Q+ U: j) K$ |- j0 s" K
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O8 I% A' Y5 G" a5 P' ]# z
所以每一条大路，! R6 V# q$ h. c; z% O
& W8 b1 e& l1 {按2珠路排列，有2种不同的路数。
& j: N4 ? r) y4 Y" r. m3 I# a4 J再举一个列子：
$ C( R6 o+ c9 J+ {' ^大路：122122122122122122。。。
5 g4 `2 Y6 \) b, Z" p: Y5 m, T按三珠路排列：
! \, ^) k& c9 ^6 G; V122，122，122，122，122，122。。。7 D6 M/ O% t. e: N( l8 B" I$ g
去掉第一口，变成：6 G2 V! \" L' c" k: d; D) w: g2 D* D1 I5 B* [5 u- E
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
D, R/ t3 v8 u; v/ Y6 z去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W5 j8 y0 V: @8 G2 ?, B
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
7 c5 n3 \% e- `+ ~5 P1 X去掉3口，又返回122，122，122，了 x! ?; S; j1 \2 G/ w/ u) T
所以每一条大路，
/ _* j7 Z% `8 ?! x' c% Q% Y4 T按3珠路排列，有3种不同的路数。
# f) G: z! H) }" l7 l同理：按N珠路排列，有N种不同的路数。! {( o1 G( b& g: O4 A
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
& U' R4 p. k' P, O5 s' ]9 d字串83 L: R) G1 V- s2 Y+ Y+ `! f1 I; Q! Z0 n! m5 C
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
; \. e2 o+ B H( S1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
- g! n1 B1 l$ z2、为三多理论提供了下注的多面性奠定基础。1 u, h5 [, b, x" r8 Q+ w" v% k
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.( D2 Z+ ]4 w. M. x
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