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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。$ s5 e% k$ d) h) J8 ?$ [0 E' }( ]4 ~
+ B, Q2 R, Z3 W1 V 假设大路开这样的路:* k% m4 `9 K( B3 n& u4 v" q2 L% K
) T# L2 A7 n$ \$ L A) x 12121212121212121212121212121212。
+ v* n# _ Z0 R3 X) L& k+ n# j) v
5 A1 v4 M: }( Y4 s! a9 y# b5 P 按2珠路,就是BPBPBPBPBP。
* x, Y( U3 D% F
; N% S& h4 V0 ~, _4 n* C 如果我们去掉第一口,就会出现完全相反的结果:
0 ?7 v6 q# o: ]' k9 |0 K! w) u- b; S3 T7 t2 }+ q
21212121212121212121212121212121。
9 j, V1 Z. i0 w1 g& U. e# X0 c- Y! `% N( `
变成了PBPBPBPBPB。
9 g7 G1 l7 u h% P) O+ w; M
2 C- h5 R: j& L 如果我们再去掉一口,又返回第一种情况了。
8 v! z5 \4 I! i2 n' F- z
( \9 T1 J4 K5 F 所以每一条大路,按2珠路排列,有2种不同的路数。
) _& l9 p0 e* d0 I3 {
# K9 P3 }- s; y 再举一个列子:
* ]/ V/ M1 q0 c. V2 [7 g6 B! V8 I8 W: a2 Y5 g6 `: W' u9 m
大路:122122122122122122。
/ E1 u+ d1 @0 p9 a( T+ [9 A+ D* ]" y6 G. o" J8 ^$ Y
按三珠路排列:
# \9 m1 o; y/ b3 y! G) r. W; q( q: R# N' @: n
122,122,122,122,122,122。7 g9 q3 o/ {- ^! Q
* ?6 i" O+ k0 B1 A# z6 A1 K
去掉第一口,变成:+ I y2 Q+ w' ^. X* s+ ~
# t( i# u& l. b7 x$ v 221,221,221,221,221,去掉前2口,变成:
3 `$ Q( o2 x' f4 r0 O1 x: j; @/ |1 m( @- U* P4 L
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。$ t0 ^9 H& T, q0 l
/ ^7 ]+ n0 F9 _4 q 同理:按N珠路排列,有N种不同的路数。
* h$ L6 v( Q5 V5 {6 ]) u0 G& Y# |% b/ j% O* x: @: m% t2 Q
我提出这个的意义在于:
8 s: L' o# b( g) O+ @* {' X
0 z3 N1 j& @& g' A( g; J, X9 `) [ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。7 Z( p$ E( o- @! T0 s
7 ] j3 q: c; y
2、为三多理论提供了下注的多面性奠定基础。# K: y9 H! Z8 h( g4 ?0 r
1 E& ?, C0 u- J( q* d& U& s, J
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。. _% u& {2 ^5 s% d' H* Y' F5 S
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