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眼里没有庄闲,只有连和跳,因为庄闲是一对一的,而连跳都是一对二的。理解也好不理解也好,这个讲起来费劲,就不过多讲解了,你只要记住百家le只有连跳没有庄闲就可以了,通常大家所看见的大路,第一行是满的,从第二行开始才有洞出现。
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; B! J# [. U- U0 O8 H 用什么办法把第二行也变满,让洞出现到第三行去呢?这就需要重新排列大路。一种全新的方式去排列大路(又是新用什么排列,用连,和,跳连就可以比如大路是(随机的)
$ u1 _. v) ~, v8 X, }* c" a5 S4 r; Q
第一行:OXOXOXOXOXOXOXOXOXOXOXOXOX(第一行永远是单跳)" V) j4 t' R5 @$ U. B) N
, p# N& r- x) \5 s1 `( |. L& z6 x 第二行:O X X O O OX O X (第二行开始出现洞): s1 x8 O7 X. \2 \
3 P" }0 {0 q5 ?. `# P 第三行:O X O X X1 V' e" J. W' v, L/ I; D0 [
: e w( U. S& ^& i4 S$ [9 D
第四行:O X X
% _! |* M" e# ~" h
, b8 h2 z+ x7 w) s6 | 第五行: X& B/ w* R' \) v. ^5 e. K m
9 K: `. f+ }7 v. @) N( P8 P 那么新写出来的大路是怎么样的呢?: j# c% Z0 O3 M( Z$ c
: Y4 V2 c" I4 D) J) \1 p
记住一个简单的口诀就可以写出新的大路:1.连是连;2.跳连也是连。0 C! G' o# d! k! o; q8 u* e0 n4 L
% t7 M! |' l4 o3 y* I% f, M 如下(大家凑合着看吧,实在不行就自己拿笔抄一遍,和上面的路一一对应。)
& f7 K! y9 ?( t% U: Y& \; Q! j; k
1 T5 i; U& ?: Y 第一行:OXXOXOXO OXOOX(第一行不再是单跳了)$ t0 f9 H4 C7 _! V$ _0 g- s# {) A
3 p9 k' K5 {# n z" { 第二行:OOXXXOOX XXXXX (第二行也是全满的)
! I0 S' R* G) Q, p ]9 F0 q/ Q1 @6 @/ w: X! o
第三行:OX OX XO XOOX (第三行才出现洞)7 @3 n' O) R) Y. T
2 P- R+ k- u; s 第四行:O XO O XXX
{! I! b; l3 E: D
4 K7 l; S7 E3 b 第五行: O$ Q0 L" |' b) U9 M8 _0 o% _6 ^2 N9 S
e1 \! H, ^1 Y# E
通过以上排列,大家看见了,变换了组合方式以后,大路不再显的那么杂乱无章了。每一列要么是连,要么就是跳连。这就似乎是最初期的关系形态变化组合排列,通过这样的排列,从形态上看,整个路只有12个形态上的跳,其他全是连贯的(可能已经有人开窍了)。* G$ [5 g- K& D+ ?
! @' a& r7 T9 x6 F 大家看第一行不再是完全的单跳,第二行没有洞的出现,第三行才开始出现洞,每一列最少是2个符号,通过这样的形态组合,实际上是减少了原本大路上的跳40%-60%,比如原来一靴牌60把,基本上是30个跳。30个左右连,而且是间隔无规律,杂乱无章的,按常规跳连的次数是基本一致的,周期越大,数字越接近。- O' D& B5 J; B2 N$ ~; [
9 k" G* c1 E( Q8 N+ T! `
通过配列 可以把原本大路的跳精简到10-15个左右,相反增加了40-60%的连,以上是对大路形态转换的最初级形态,相信已经能对大家有帮助。至于怎么样去下单 ,一目了然了。
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