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6 C+ T/ b+ Z! t2 l& W$ r- Y, F
# x; L* w% [! R; _$ w. K# a通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
' G6 L. p: _# ?# r, B; p/ q/ g4 H9 b* o
假设大路开这样的路:
4 y5 t2 V- `# N; O! D- I" a5 v, A2 c: X# w
12121212121212121212121212121212。
: _' _1 X0 _+ E9 i
: i$ N! L! J7 E! S ^ 按2珠路,就是BPBPBPBPBP。
* q4 c d2 U6 R1 X$ T1 g+ B7 c! \( q. @5 c
如果我们去掉第一口,就会出现完全相反的结果:
8 _' p" P- g3 W8 O: N8 L% \8 a% @ V( |0 n
21212121212121212121212121212121。
3 L6 `$ U9 c% I6 ?* c, ^+ X0 Y$ j% F$ @. P6 B0 {8 v4 e% S' r
变成了PBPBPBPBPB。
# E- c4 G! k3 w3 Q1 S% i; e2 k& C( k8 c! ]
如果我们再去掉一口,又返回第一种情况了。" B. J1 S% x6 c2 e1 w* M: ~
+ v+ Z& h$ Z; Z! v8 |/ P; Z 所以每一条大路,按2珠路排列,有2种不同的路数。1 `5 T3 `. j9 \3 M. O1 _% n
/ u# j! ^- m; q$ P) g 再举一个列子:( @. _6 U, B, W7 S$ i7 ^
* C: M3 U4 x4 M- O5 [ 大路:122122122122122122。
- o0 a( a, o7 C( X) I0 x2 I. A2 G2 e0 y Q9 @* ^+ V1 O* A
按三珠路排列:
; ]; G" u8 Q4 g& |
/ j0 g( g! k# o$ M- k* n) R3 M 122,122,122,122,122,122。
8 H9 `/ [4 M* N* r" ^' _- P7 ?6 K
去掉第一口,变成:
! A6 `# p0 i3 V U; {6 ?6 l7 {
221,221,221,221,221,去掉前2口,变成:+ |* y j- t2 X2 l; C
) M& S; x$ l, E& W# b 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。+ f' @5 W3 l" E& u5 W
. X: G5 }) U' R$ {' F! Y 同理:按N珠路排列,有N种不同的路数。; i: j0 s: m- V
0 {( B+ \+ @! _6 k0 e9 c
我提出这个的意义在于:
5 _$ G$ G/ T. r9 Q M& V0 m6 o( U# l: y s- H- Z6 J+ z$ N
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。4 Q: Z+ T9 i' n% U' k9 H( _! {. N* ~
$ T# `' j) n, R& @2 `/ ^% x 2、为三多理论提供了下注的多面性奠定基础。. o! H0 Q# f+ p/ E1 `7 g$ v2 ^
8 p1 L4 i# i Q8 A2 l 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
3 f7 S, [- u8 }( L1 y, c" |- P, U5 [9 h" _ ]7 @: w
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