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通过我几个月来对珠路理论的研究,
# I' d" R; c$ `- Y4 M0 ]/ n# Z* j; A1 d. d7 f2 o# o
发现了一个有趣的现象,, `7 Z6 Z/ ~6 }1 a8 d" p0 T6 P
每一条大路,
! s5 N) i1 z9 o+ E' S; _按2珠路排列,有2种不同的路数
* j4 i. |( g, w" C2 l4 M! n! z按3主路排列,有3种不同的路数
/ c$ m: W) W4 j; h3 [ x9 R按4珠路排列,有4种不同的路数3 h2 W- N% _+ R# l
按N珠路排列,有N种不同的路数。" H9 @$ S7 G: v/ P4 W/ g0 O4 ^# L R
什么意思呢,可能大家一时不清楚,
. `7 }4 g3 w1 Y' U我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
/ _' h. J% e- D3 z假设大路开这样的路:# j- Y0 x1 `9 L6 ?+ F d
12121212121212121212121212121212$ |( ^. M) _0 C+ b& {
够极端了吧2 t9 Z# T h! p: [( g
按2珠路,就是BPBPBPBPBP.....
- x: _, b) m& l# ?8 _6 b如果我们去掉第一口,就会出现完全相反的结果:
& Y3 w8 a0 Q* {% o+ |+ F- ^- _21212121212121212121212121212121
0 v, e/ ~( _ L变成了PBPBPBPBPB.......2 J( \) P6 ]$ f& `3 r5 y/ ?
如果我们再去掉一口,又返回第一种情况了。9 r3 v2 {5 l0 W# u$ z' Q) H
所以每一条大路,
- Z5 W3 L# a% O1 X4 y按2珠路排列,有2种不同的路数。
0 W/ r1 `; j/ g x3 p: Q5 A* b7 P5 G再举一个列子:
) {, M% v& I! e+ ^大路:122122122122122122。。。$ a5 i9 j6 K+ M$ P- v
按三珠路排列:
6 E( r( ?/ z2 s7 @; a122,122,122,122,122,122。。。3 \1 y5 ]- ? l7 v
去掉第一口,变成:$ @, w6 z- s& H
221,221,221,221,221,
9 T+ l) N2 D) S5 }- v" }7 ~) a' T去掉前2口,变成:
9 h" R+ ]& G2 C+ [4 @8 T$ A$ ]; k1 P212,212,212,212,212,
& E/ e( v8 T7 X; }7 b去掉3口,又返回122,122,122,了
0 u! V5 c% ]9 v* Q$ O& u9 m. z- G2 I: o所以每一条大路,
/ e+ Y7 n. A2 U$ k; g& h% n/ ^按3珠路排列,有3种不同的路数。9 |4 m. j3 F( L& a
同理:按N珠路排列,有N种不同的路数。% H" ]: Z) A6 a2 N
我提出这个的意义在于:) R! I/ z2 z# U% ?# N" p
字串8
/ ]! z# |9 |' ~ |. J! }
% f" @# L1 ~7 l7 e* T1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。3 d9 H% z# L2 u/ b: x( c' r
2、为三多理论提供了下注的多面性奠定基础。
0 K H) Q6 F/ h: Y7 P8 @8 k3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.. W4 J$ @( s8 K( y( F3 R
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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