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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
3 a, ~6 f: [1 u! y
: O2 O$ O) Y& t发现了一个有趣的现象，
5 B# }3 n7 U- [. k* a0 ?- y每一条大路，; T S. f) ], K+ w6 ^1 V u5 f
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f8 U4 g4 B3 a5 Q! \1 e5 p8 F" b) e+ N
按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z1 ~7 D% U M A, _ [7 q
按4珠路排列，有4种不同的路数
1 g3 A5 w( y0 W5 F按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
( B/ c" h6 `3 w0 M3 l什么意思呢，可能大家一时不清楚，
0 U) h9 O& K+ _$ v/ k我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
' h$ k9 y, y. g& x+ ~/ A3 m! _假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
. w F* q; c( e- U9 T12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h; I' C) V5 ]% K8 J0 V/ g( b
够极端了吧6 X; T* {& Z3 e
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F% k, @* |( o' Y/ [% |* }
如果我们去掉第一口，就会出现完全相反的结果：9 _; ?8 }/ b8 U" ^7 M) g! b* O1 T6 ^
21212121212121212121212121212121
0 V/ B, Q/ B p: }变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C/ [, A: }7 l8 t k& o7 G& U
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O! v! L2 S/ E M2 t/ B9 N/ n
所以每一条大路，! R6 V# q$ h. c; z% O
& K, l; K, p4 c3 w1 C- ?9 Q按2珠路排列，有2种不同的路数。
2 o: T4 ]2 j t. ~再举一个列子：) L2 f6 m% D3 P/ d( d5 e* l
大路：122122122122122122。。。* |; U! L+ q! ` b9 j) D
按三珠路排列：
# S( n" s$ c( l122，122，122，122，122，122。。。2 O) \, F5 X7 [) c, n8 ]* p
去掉第一口，变成：6 G2 V! \" L' c" k: d( }9 d; U8 Z; H' g9 e
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
) S: x+ L% [. x- O去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W: V$ b5 R* h% k4 i/ ^3 W0 g
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `4 m0 M# u! u2 {
去掉3口，又返回122，122，122，了
, X& K* j/ [3 _6 P+ I0 m所以每一条大路，
7 h5 s" ?5 R5 k/ b' a按3珠路排列，有3种不同的路数。
/ v3 k; k: m8 _- }) S同理：按N珠路排列，有N种不同的路数。# n4 r% y0 t1 \. `1 C
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
) s( F& |. x) |, W( P( s9 L/ E) J, e字串83 L: R) G1 V- s2 Y+ Y
f/ _: S) ?- J. ]- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
' M. [; p) b- K/ H0 `/ q( H# P# }1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
9 a( X9 Q% s4 I. Q3 y% z. n2、为三多理论提供了下注的多面性奠定基础。
4 d1 V8 P; p% s$ w# b N4 v- w3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路./ ]- v2 s1 I% a( q) ?( h& K) R
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