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+ L- M& M" K; w/ m. j
. e4 i1 n+ k0 L; z1 j通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。' \8 p: ?1 L. q7 E/ }5 y) v8 s Z
7 O$ I" r' e9 e% D6 `. E
假设大路开这样的路:
" ?5 B3 D1 x2 q, K i6 _" I6 T$ _3 o# P1 h. b4 x. o
12121212121212121212121212121212。
3 F' U% P8 M" D/ a( A! V3 Y; U3 p; T3 k! @, S! G5 m4 G/ v: o
按2珠路,就是BPBPBPBPBP。* }0 B5 x* y, x8 V# Z+ c
, `! X" D2 g/ \& b/ G4 f
如果我们去掉第一口,就会出现完全相反的结果:
) F; S. F, D$ H# w0 \' x. n0 d8 ?6 R5 }
; e! y8 Y3 }: N' s" y 21212121212121212121212121212121。0 N0 m; d% ~$ A+ X! U
3 ? U: F3 z, X" @7 }4 b
变成了PBPBPBPBPB。0 l- y4 N- V6 a1 P6 b3 }
3 W5 t* C) O* t' \0 J8 n 如果我们再去掉一口,又返回第一种情况了。
! P8 B7 O. x, A' I- Y& O1 B) r& ]) H1 ]- T% Q3 g& P6 U
所以每一条大路,按2珠路排列,有2种不同的路数。( q# C# c k! ?6 \
6 O# G4 t R0 A6 ^( V& e 再举一个列子:
/ @9 R! c9 d+ M0 F1 x9 [; ]4 S
8 n; L- O+ W1 t! {. |$ R/ | 大路:122122122122122122。
- H# ~% T$ h" i2 Q$ x w" _, H) F- d% ~
按三珠路排列:
1 C+ C- h+ u! _6 j- J. i' t! x% {% y3 X( R' e
122,122,122,122,122,122。
+ v5 D/ z# E3 `5 H4 n" z& G
_+ u9 D/ Y# x. ~; ` 去掉第一口,变成:
, f( J) W Y8 a# Y+ E1 H+ Q6 T- W+ X. s% Y
221,221,221,221,221,去掉前2口,变成:& h; b j( U& O F- Y9 Z
- U# O, r6 M2 W
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。 {7 W6 W1 p3 [2 u
0 i7 e; v: O$ C; X 同理:按N珠路排列,有N种不同的路数。
8 A( x5 }* y; u0 T$ D' a/ A, o I2 ?5 `; q3 x8 G# _. J
我提出这个的意义在于:% Y: Z( h9 Y. U: ?4 s
9 ~4 C- Q0 m$ f* j
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
7 D4 [$ K7 g3 D% @- v
' G( e2 S4 \. |, i4 M* d* |$ I 2、为三多理论提供了下注的多面性奠定基础。. C `: \8 r3 _; x2 S) A$ D
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。# c+ D, @5 e* U4 T2 U D
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