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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。# }/ |6 y2 ]9 f, V8 d8 n! j
, R, F7 {0 F* W( l& d6 Q+ W+ n 假设大路开这样的路:$ t( N2 T3 p* R% G9 z$ `1 F
3 A0 J7 F4 A4 H8 {. V2 Y 12121212121212121212121212121212。
: R1 g) c$ |$ H+ V/ ~( P' z: t( e% i, s1 E2 T1 ^
按2珠路,就是BPBPBPBPBP。2 w4 K2 @6 S$ r
2 C" @9 y! Q5 u, m
如果我们去掉第一口,就会出现完全相反的结果:- x* N/ Y$ y$ T' P
1 p% g; r ?8 H1 O! _8 J3 s! |- F: k0 T
21212121212121212121212121212121。& @5 c. Y$ u' i$ n: [& d+ k) S8 ]
1 D/ ~) P q( m6 b+ i 变成了PBPBPBPBPB。
5 l) b9 t7 ^& q. V" a. ]) p3 A8 [" z$ g2 E- x8 ?: G$ [3 I& u9 a4 G; N% r
如果我们再去掉一口,又返回第一种情况了。 ]& d; C/ r% u n6 J- x
}2 e* \" J3 g- ^2 s0 I 所以每一条大路,按2珠路排列,有2种不同的路数。
/ t: [- Q5 D- O1 `- ?) e. G6 q2 _( q% |
再举一个列子:
2 z) I6 b! Q& b8 \, H3 F/ C+ B: H1 |$ O' d/ \5 W2 B9 f8 |
大路:122122122122122122。2 a, D3 t4 m3 O
" V2 ?3 _! V; E+ x# d3 _ 按三珠路排列:6 m( t5 @- \6 K. g( F9 `+ w
0 h. Z. C6 l- w2 U0 H7 y w0 X+ s 122,122,122,122,122,122。( {: z; t* c$ M' f9 P* U# j& h/ T- @2 L
, j5 e- O8 ?/ c! W
去掉第一口,变成:+ P5 u# f) E1 V$ w; J( ]
$ g+ ~" z1 e2 ?2 S) }+ m 221,221,221,221,221,去掉前2口,变成:; a7 n' o0 C& N' Z! m; w
; y% C$ u# w: Q( x4 T5 y! p k
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。& u; D9 W1 M& g0 z8 T
+ _! V9 Z# U7 L6 R+ u$ e 同理:按N珠路排列,有N种不同的路数。
0 N/ g$ l0 {: x: Q
( Z: t2 ^+ n9 z+ L1 f 我提出这个的意义在于:! f* J; S; f' D3 g) E( @
% f( D5 _0 W4 I" b/ B 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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8 S t! I$ t6 E0 u6 p7 w. |) X 2、为三多理论提供了下注的多面性奠定基础。+ d9 |; T3 ]: r
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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