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+ ^7 D3 u2 }/ o* z
5 A* G$ H; j% q" W7 B+ m. v- C通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
/ n% {9 u, l4 i3 ]% I, f) @1 H
/ Q/ o ]# I2 M0 v% m W 假设大路开这样的路:! P: O' T( W# M
7 ^3 X3 p/ O& I5 H9 G( W2 S( E0 H 12121212121212121212121212121212。0 u4 Q. s# g" K; t7 L5 S
* x( A: v" U' \- Y 按2珠路,就是BPBPBPBPBP。! D) ^& Y% n& [4 c
* E: i6 m# [2 l C9 V& `1 T) B 如果我们去掉第一口,就会出现完全相反的结果:, T! [6 ^- n9 Z8 P
$ P( U' L$ @0 p7 s+ P 21212121212121212121212121212121。6 C8 H5 S6 r2 G7 z! r) j
, w3 Z( Q( v/ N. g: R 变成了PBPBPBPBPB。; }( ]+ i0 |; C% Q {; s
: E: o" a6 Z; b7 S8 R4 v. M" C 如果我们再去掉一口,又返回第一种情况了。8 S: b% [7 A( i+ j
( |) g+ Z" L+ x 所以每一条大路,按2珠路排列,有2种不同的路数。' v% n8 d! Z; X: [0 D$ [1 L: }
; e( ~( p7 A8 W6 Z) A% ?1 L2 d" G
再举一个列子:
7 c7 q. `2 `; q, a2 T; T# q# R0 Z3 a3 `! I3 q* \, S0 @- h
大路:122122122122122122。" G# c- F2 ?4 d$ m
0 m" s. `% ~5 W3 G 按三珠路排列:
3 V, `/ V; X; _7 R9 j; G2 a9 Z9 q% ] T- q2 ^- d
122,122,122,122,122,122。4 u- [4 g+ r. d- z$ u/ b% B, ^
) q5 i7 K* u2 _# k ]; J6 o
去掉第一口,变成:! n, q+ L- n$ P6 V+ q
) z. K( X' c$ |5 e$ H. J' S1 d9 ^ 221,221,221,221,221,去掉前2口,变成:# K& s: I& L/ W6 U
1 e& {4 \6 A# C
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
! D" s+ k7 j+ }, j! q' M" ~9 A+ o2 F3 G% u, A
同理:按N珠路排列,有N种不同的路数。6 s& t9 d. f8 N! [3 e5 a' N
' S) F% i/ k( M! C8 N
我提出这个的意义在于:. k G7 @/ `4 n
2 P; k# `1 q' h- ^: ]) @: K6 M9 i7 c
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
4 C6 F, C# e |; }& a! j" B1 U6 X- p$ D) H" C; |
2、为三多理论提供了下注的多面性奠定基础。
6 ?4 o0 m" M: O8 J8 M# ~! t$ B' d
/ x; M$ d3 G O 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。5 n2 I5 ^" e7 e! y/ s; F0 G9 ?! [0 J
4 f1 B' T1 y8 _! |- C, L
7 _% g) k8 g: Q+ n% e" k: n% l( m8 s$ {1 }: d( e& R
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