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“四二法则”是一种估算概率的方法,让你能快速计算你想要的牌出现的概率。4 l7 E8 p' s |7 f' Q7 K7 o
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比如:桌子上的牌是A-6-7-Q,而你的手牌是8-9。你想要再来一张5或者10来凑成顺子,但你只剩最后一轮机会。
8 ^/ i' g) Q/ y
" ~6 @2 \, T. g% G8 v$ f严格来计算德扑概率应该这样:1 V: T; } d+ G
" Y7 j5 L3 b2 t* \一副牌52张,去掉翻牌3张,转牌1张,手牌2张,剩下52-3-2-1=46张;) w* j0 k2 f! @
$ [, S5 ~* a0 N' j# X* G7 y7 E你想要的牌是4张5和4张10,共4+4=8张。
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( }! g. `' C/ H- b; b那么此时,你在河牌中顺子的概率为:8/46=0.1739,即17%。! F& R+ K m& E/ Y7 M, r* A/ p4 g
! [0 \2 U% D* P7 A% U9 Q你可能觉得这样计算会比较麻烦,于是就有了四二法则,即:你想要的牌有4+4=8张,
: P" y0 a+ I1 a- [2 x) k% ^0 n% c, ]$ @0 r e5 Q
只剩最后一轮机会,所以让8*2=16,即你有约16%的机会中顺子,与上述17%基本近似。: \1 z: R" q" d) k' T: W% b' m! F. D
" [6 c; c; n P0 ~这是四二法则中的“二”。/ l' i4 ~" ?+ l; C4 J; ~! e
2 h W7 z) `, W! n) f3 a! D当然,如果你还有两轮机会的话,即河牌圈与转牌圈,情况是这样的。
' Z4 y+ n1 R* ~' f5 \7 N: p! R
0 u( t# S2 Q, i比如桌子上翻牌为A-6-7,你的手牌依旧是8,9。
0 Q0 M% t# e1 [ ~& z6 W" @0 Y* L+ h B! P: F
不一样的是,你有两轮机会来等5或者10,共8张想要的牌
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. M7 [. ]7 [2 n, J! L3 s: d4 D那么两轮内你中顺子的概率为:
% q4 e0 u! T8 ^6 [ n. e) e! b" E g6 @2 W& o
1-(47-8)/47*(46-8)/46=0.3145,即约为31%。( d2 m: C2 s9 K' r5 v! p5 ?
$ L2 W9 K2 W% \! P) j- p4 i8 K那么利用四二法则,8*4=32,即你约有32%的机会中顺子,是不是跟理论值也很接近。
' w `1 u) a1 ^/ F: e
' n0 o9 p$ Z4 P9 w; h* p+ ~) x这就是四二法则中的“四”。+ e2 l9 H. a4 m6 w+ g; D; {
0 N5 a" X2 t/ T+ T0 a! c1 F* m9 h* g总之就是,先想好自己想要的牌的张数,然后,还有两轮机会就乘4,还有一轮机会就乘2,得到的就是你想要的牌接下来会出现的概率。接着,根据真人德扑圈的游戏玩家以及战况来决定接下来该怎么办。利用好四二法则,可以帮你快速估算概率。
/ u% ^* x7 X' i6 U( J9 b) p
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我现在还是研究一下理论打法,感谢楼主的分享,我也来学习 |
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方法最后一段话觉得是实用的,但是在我面前就难以实现,毕竟运程太差了。 |
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