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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O- L! E0 }7 J6 s! f" b
9 I" O! [$ Y+ }2 c发现了一个有趣的现象，
0 w* |+ W; Z7 T+ y5 O w每一条大路，
. s& s2 X; y* |( ]( ~5 }4 e按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
1 ^5 m; @1 \2 y按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
- S; N- l8 q0 U3 ]1 A0 r% D P按4珠路排列，有4种不同的路数" h/ ^+ ^ y% s# R; n8 u7 V5 Q6 M
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C) P2 E* ?7 O9 U3 b" u
什么意思呢，可能大家一时不清楚，
* }& f2 ~6 L7 _- ~' H我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
0 g1 Z/ @% [8 N& ^4 v8 q假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
* X" P$ g7 t- A2 t0 x12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
0 f" {8 M1 R* E1 X/ `够极端了吧# r" k$ ~" W5 ~
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
1 _/ H4 v5 ]# e& P如果我们去掉第一口，就会出现完全相反的结果：0 f( e8 {* A+ q, T' X$ `
212121212121212121212121212121214 c0 b! F& g2 G' {
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C; @2 `& f. I8 v0 W1 R( n3 y6 v
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
9 L$ U% U Z1 a& Y: b所以每一条大路，! R6 V# q$ h. c; z% O C) D3 G0 K4 @8 P+ V1 \
按2珠路排列，有2种不同的路数。
* g3 i: P% V% X) _& x再举一个列子：
* ~; y% @8 l7 j) g7 c- @$ d0 X大路：122122122122122122。。。& u" [: J1 s+ y$ ?6 P' }) G0 P2 _
按三珠路排列：4 m) ^8 ]) B' K* `. H5 _' e5 j
122，122，122，122，122，122。。。
. U9 d9 i- w, T- d$ V! S& B去掉第一口，变成：6 G2 V! \" L' c" k: d
X0 f: c& `, r221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
& B: k" H9 I* e G, }去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W' z! |3 q- A+ t
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `! J+ H Y2 s* |4 Q$ U7 Q* B6 D
去掉3口，又返回122，122，122，了
C- j I+ B1 ]8 p( F所以每一条大路，
+ g# Z/ {, e4 U& l5 \' \8 N0 M按3珠路排列，有3种不同的路数。" x) X/ ]& C- W" K9 V
同理：按N珠路排列，有N种不同的路数。3 Z1 n# J' V5 Z+ d5 Z
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
, o' U3 d. C0 q p" C字串83 L: R) G1 V- s2 Y+ Y
' u1 A: g% X" u- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
, o+ T S' S/ |/ F( Q, L1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |/ r/ j2 Z( e4 B( T( k
2、为三多理论提供了下注的多面性奠定基础。. j2 F1 |1 s8 O4 ]* R8 g; A+ O
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.
/ P/ H r* _* g$ } |
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