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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。6 `$ H! x. {2 [7 T. v0 ?: ^1 Q
( z$ g% q f; q/ {# j0 h( M 假设大路开这样的路:% G% C8 E! P# K3 y! {7 |
; b1 q: s9 j' L9 H 12121212121212121212121212121212。9 J6 W& Z0 F$ Q( F
# m- G3 H( m8 t' S n( {' G 按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:3 o* O; N- C* R- r$ x) t# i1 ]
* I7 k; F' k, ~) L$ c
21212121212121212121212121212121。% c7 Z5 D( \& ?" S
; }9 j$ c: x' e 变成了PBPBPBPBPB。
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2 n9 a: Y- G+ v( Q! F4 A 如果我们再去掉一口,又返回第一种情况了。
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所以每一条大路,按2珠路排列,有2种不同的路数。# H$ K* Y6 B! h
; k$ w, \: U( K7 B 再举一个列子:
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大路:122122122122122122。% m# W4 {, }- q3 \( G6 _
( Y; G" o, y) V+ z% j% B) u6 b& U 按三珠路排列:
4 ~' o- w9 y3 Q. q* C8 O8 }5 i% H6 g) v. Q; d$ Y
122,122,122,122,122,122。5 S% ~7 v9 q S. ^! U( x# X$ j/ \
" s$ ]' J5 q0 o' ]( g 去掉第一口,变成:
1 y8 A! T: _6 U9 M. j; G$ P
1 K' }9 |* U2 w 221,221,221,221,221,去掉前2口,变成:
$ D0 v# Z+ @7 V! S( {/ r4 D: p) k5 j$ Z
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
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同理:按N珠路排列,有N种不同的路数。
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& H( ~" P9 C2 c 我提出这个的意义在于:/ J; U- B5 G6 X; m% Z; F# t) ?
. r8 W! I" l/ f4 O! s6 n: X; h
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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0 p4 P# V9 W! u: R1 N) c1 N% _ 2、为三多理论提供了下注的多面性奠定基础。( x6 ^: r; S) a
2 V6 ~+ z8 g0 X& n 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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