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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O' h8 k) {$ I" i j: ?% f
# n$ H7 B$ B) o0 U% }- W5 _
发现了一个有趣的现象, L% u# j/ h' ] y5 x
每一条大路,& |( C; y t% d& A: |8 L5 [
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f
2 M: e0 _( D* ~- a. }按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
3 p2 a k! G' l2 F3 e; Q按4珠路排列,有4种不同的路数2 g: y8 j/ U. ~* b
按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C
: w) K, Y. Z2 d+ T什么意思呢,可能大家一时不清楚,& }1 x5 U- u; [, A, ~) m$ T7 }
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
, M. C$ g: S8 Y$ n$ p+ `假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u( I2 i. x$ Y% {+ D2 I9 v+ ^( ]) U
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h/ O- G$ l0 ~8 s3 W$ S" o. w
够极端了吧
7 A* `& i7 _- r3 J! b按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
! i8 n: ^+ V% g/ X4 `! _如果我们去掉第一口,就会出现完全相反的结果:' z/ X1 B D! I" G' Q- {; u
212121212121212121212121212121212 L; G8 i/ ]5 l Q. h, P0 z# R0 ]
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C0 Z4 u) P. J# T% p, Z
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O/ C) m% F" T( l6 l7 q
所以每一条大路,! R6 V# q$ h. c; z% O
4 Z3 z! S. C; Y2 d! [' ]按2珠路排列,有2种不同的路数。
/ A5 w7 R- d, ?再举一个列子:. [* | E8 K% u. r4 |
大路:122122122122122122。。。* D3 p$ u. r: A$ J- d5 S
按三珠路排列:
: M5 b1 X7 a' }8 b2 o7 Y' ?1 n122,122,122,122,122,122。。。
. T! P i+ C5 E1 m去掉第一口,变成:6 G2 V! \" L' c" k: d
/ X+ p# X2 A6 _: }: e, M3 P221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M
; [- `' g6 w% L6 z0 S9 L; W' `去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
: |% W+ p, U d' d8 s" ?212,212,212,212,212,: y& l, B; I6 e- m. J# c) `3 L* }+ ~1 R. C
去掉3口,又返回122,122,122,了4 Z" n A0 A. }" d- J1 s4 [' N6 s
所以每一条大路,) ~$ m. d S- e F3 W
按3珠路排列,有3种不同的路数。
: K V, B9 |; A/ Z9 _2 M- b( l8 U同理:按N珠路排列,有N种不同的路数。& y: w2 L; u" H( V0 K6 C& [: j- g# g$ P
我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
3 U' c) s9 ]7 \& j: W字串83 L: R) G1 V- s2 Y+ Y
6 q% A u7 q" m; {* Q9 s5 A- p, d3 [6 U. s5 J' [0 {1 A" m' k( @! j! [) s' b+ g4 G) h, }/ ]4 V/ |
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
+ e0 a2 }- s, s) b6 S- B& y2、为三多理论提供了下注的多面性奠定基础。
! k K* z* G9 Z9 c* f ^9 V3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
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