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[打法交流]
近期在网上研究到了个百家乐著名战术 蒙特卡洛战术
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百家乐蒙特卡洛战术,需要纸和笔。但是不很难。0 D4 z2 P( x5 v5 ]
6 m/ E- }; R4 f v(1) 首先写「 1 2 3 」的数列。: ]+ F& A' H6 [2 W
+ Q8 R! D9 M+ x: }+ E) b(2) 赌本就是左端的数字 (1) 加右端的数字 (3) 即是 (4) 。! M2 Z* @9 n0 x
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(3) 输了的话就在数列右端之外又加上顺序的下一个数,现在这个例子要加的数字 (=4) ->( 「 1 2 34 」 ) 。如此类推,并且重複上面的第 (2) 点 ( 但今次会是 (1)+(4)=5) 。$ U) L) @; ~: A9 t9 c5 o p( c
0 @: L7 ]5 m P/ m+ v(4) 胜了的话,倍率 2 倍的游戏就把左端的数字 (1) 和右端的数字 (3) 消去。倍率 3 倍的游戏从数列上去掉左端的二个数字和右端的二个数字。
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! o, @' |) `4 [, w% f" P(5) 如果数列所有的数字都消了就代表结束。 K( Q0 v7 s- N0 p" x
, C; S4 F) ~- H& r! s, g, f(6) 想继续的话,回到 (1) 。
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蒙特卡洛战术的问题,在于如果没有充分而源源不绝的赌金,就会出现途中被迫停止的可能。而且连败的话,亦有机会超越 Max Bet ( 赌注的上限额 ) 。
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二合一战术" ~$ R5 @0 c, \' e! I
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这个可说是蒙特卡洛战术的一种,是以 1 局取回 2 局所输的方法。方法简单。写下输了的金额,赌注就那个左端和右端的数字的共计金额。 J. z7 e- o1 y* D/ f" h0 s
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譬如,先写下「 1 」。所以第一局的赌注是 1 。如这局输了,右侧添写 1 ,成为「 1 1 」。那个下一局赌注将会是左端和右端的共和 =2 。: D( J* s7 W4 s8 }* H: \6 B
' ] {. `) v. t' F& N# c0 L反复这样做,如四连败,数列将成为「 1 1 2 3 」。因此下一赌注会是 4 ,而且胜了的话,消去左端和右端的数字,数列将成「 1 2 」,下一赌注就等于 1 和 2 的总数 3 。再胜的话,会变成?
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! ]) s* ~1 N* b9 B儘管结果是 2 胜 4 败,共计收支是一加一减等于零。) _, B' V2 k) j
4 e2 r. }7 o. p) m9 b这方法我试了不咋地,你们可能可以?
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