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这么难,大多数人很难理解吧。理解透的人,请帮解读一下啊 |
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; [- ~; |- _4 I8 O$ J谢谢对兄弟对我的软件的肯定。:lol' u9 X( T) j* U* W7 {& l6 W
请问你对LZ这个方法怎么看啊,能理解吗 |
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揽1,揽2,揽3,都赚了1,总+3。但揽4断了,-1.-2.-4.-8,-15码。
, w7 _+ V+ W8 M0 C" k总的应该 -12码,而不是 -4码。0 x8 F& W7 t2 c" y! ~4 R
赌神,难道4条揽任何一条,在第三手断(-1.-2.-4)之后就不上到8了吗?
4 I9 q9 k: C, v, Y3 i. l, J不是大家不理解啊,而是计算后,很明显对不上帐啊。 |
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& J: A% D8 o0 m, f6 J
我擦,你对我也太了解了吧。" Z8 S% r' u* X+ A: J
刚回去看自己帖子,发现你那时还问我一些问题呢,现在就成赌神了。
, p5 s& O, N. y9 G# F* v不过悟道这个东西,总有些人天资比较好,一点就破,有时真心羡慕嫉妒恨啊。
' G' |9 d: Z- j& L谢谢你的提示,等下就去排列一下这些组合。 |
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小赌怡情 发表于 2014-1-2 21:56
1 `' c- _( B+ y1 a8 k9 m+ d& c, v+ s开始 揽A-1-2 再投一把后结果变成 揽A-1-2-4 实际是总输-2码。理解揽转为 揽A-1-2 不知是否正 ...
( b- f; ]0 u/ A- N5 \如果这样,打P,但出现BP,那么. P' s# G3 L' y# V
A -1 -2* i* t$ P% s$ z+ g7 l0 W
B +1
1 g9 y7 {9 N5 K* m- ~3 X5 ?. y2 Z aC -1 +22 d! b# O$ u, o1 y! C; C, w7 R
D -1
" {. V+ L( C5 f, w6 J9 ^; x5 D
4 ^8 z- v6 M: |% q出现P就结束了,因为揽没断,结束了。这时候是不是亏2码? |
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原来A的BBBB周期为28,输2个BBB的揽本,2*7=14,改写死亡图后就是 -1-2-4-4=11,14-11=3。平均1个周期能赚1.5码,是这样的吗?6 S1 j2 h7 i R
然后再计算B,C,D概率,然后ABCD相加,对吗 |
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避免死亡图连续发作,连续发作是等公车问题吗?要来一块来 |
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; @7 ?( h4 F4 \; v" ~; j9 B能做到长赢,但跟必胜法无关。我还是没办法理解必胜法,无论怎么计算都是零和。 |
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4 ^8 d& b9 Y' R. l6 A4 H8 s等公车问题是著名的11路公车数学问题而已,不是我的比喻啊。 |
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1 J. `3 b1 N3 ^3 j9 d" V, e! K8 c$ D
必胜法
$ @; f7 t* a% S, D' P k6 h1.2.4.8.......到无限大,必胜的。
) B9 I/ z1 j& R2 H8 l# c只是.....振幅太大。! l; V# u9 s' L% z% V, x
如果有办法把振幅缩小,再缩小,那就可以用1.2.4.8 必胜了。可惜我也不知道。 |
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7 Q& H y8 @; z n. F _8 q! q4 }我也不知道啊。但感觉方法虽然是必胜的,但操作不好一样没用。 |
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